3. The velocity of particle A, t seconds after its release is given by va(t)=3.5e^0.8t meters per second. The velocity of particle B, t seconds after its release is given by vb(t)=11.8t-0.4t^2 meters per second. If velocity is measured in meters per second. how much farther does particle A travel than particle B during the first ten seconds (from t=0 to t=10)? round the nearest meter A. 12,847m B. 12,581m C. 12,447 m D. 12,585 m

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