Zookal
Zookal

We’d love to hear any feedback or comment from you!

© 2011-2021 Zookal Pty Ltd

View question and answer

From our collection of questions and answers
Science · Chemistry
Question details

A solution containing a mixture of the compounds X and Y had an absorbance of 0.760 at 443 nm and an absorbance of 0.652 at 520 nm when measured with a 1.00 cm cell. The molar absorptivities (e) of X and Y at each wavelength are shown in the table below. Wavelength Molar Absorptivity (E, M-1cm Y A, nm 14050 3315 443 520 3418 5.500 x 103 What are the concentrations of X and Y in this mixture? Number Number [Y] M

Answer
Find step-by-step answers from expert tutors to questions asked by students like you. Start 14-day free trial.Find step-by-step answers from expert tutors to questions asked by students like you. Start 14-day free trial.Find step-by-step answers from expert tutors to questions asked by students like you. Start 14-day free trial.Find step-by-step answers from expert tutors to questions asked by students like you. Start 14-day free trial.Find step-by-step answers from expert tutors to questions asked by students like you. Start 14-day free trial.Find step-by-step answers from expert tutors to questions asked by students like you. Start 14-day free trial.Find step-by-step answers from expert tutors to questions asked by students like you. Start 14-day free trial.Find step-by-step answers from expert tutors to questions asked by students like you. Start 14-day free trial.Find step-by-step answers from expert tutors to questions asked by students like you. Start 14-day free trial.Find step-by-step answers from expert tutors to questions asked by students like you. Start 14-day free trial.Find step-by-step answers from expert tutors to questions asked by students like you. Start 14-day free trial.Find step-by-step answers from expert tutors to questions asked by students like you. Start 14-day free trial.Find step-by-step answers from expert tutors to questions asked by students like you. Start 14-day free trial.Find step-by-step answers from expert tutors to questions asked by students like you. Start 14-day free trial.

Find step-by-step answers from expert tutors to questions asked by students like you. Start 14-day free trial.Find step-by-step answers from expert tutors to questions asked by students like you. Start 14-day free trial.Find step-by-step answers from expert tutors to questions asked by students like you. Start 14-day free trial.Find step-by-step answers from expert tutors to questions asked by students like you. Start 14-day free trial.Find step-by-step answers from expert tutors to questions asked by students like you. Start 14-day free trial.Find step-by-step answers from expert tutors to questions asked by students like you. Start 14-day free trial.Find step-by-step answers from expert tutors to questions asked by students like you. Start 14-day free trial.Find step-by-step answers from expert tutors to questions asked by students like you. Start 14-day free trial.Find step-by-step answers from expert tutors to questions asked by students like you. Start 14-day free trial.Find step-by-step answers from expert tutors to questions asked by students like you. Start 14-day free trial.Find step-by-step answers from expert tutors to questions asked by students like you. Start 14-day free trial.Find step-by-step answers from expert tutors to questions asked by students like you. Start 14-day free trial.Find step-by-step answers from expert tutors to questions asked by students like you. Start 14-day free trial.Find step-by-step answers from expert tutors to questions asked by students like you. Start 14-day free trial.