Differential Equation:

Given that y1=e^t and y2=t+1 are solutions to the below differential equation in it homogeneous form: ty'' - (t+1)y' + y = 0

a) verify that y1 and y2 are solutions to the homogeneous form of the DE.

b) Using variation of parameters, find the solution to below non-homogeneous DE:

ty'' - (t+1)y' + y = t^2

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