Given the following information, calculate ∆H° (in kcal mole-1 ) for: NaI (g) → Na+ (g) + I – (g) Process ∆H° (kcal/mole) Na (s) → Na (g) +26 I2 (g) → 2I (g) +36 (per mole I2) I2 (s) → I2 (g) +15 Na (g) → Na+ (g) + e– +118 I (g) + e– → I – (g) –71 NaI (g) → NaI (s) –48 2Na (s) + I2 (s) → 2NaI (s) –69.9 (per mole NaI) a) –18 b) +7 c) –85 d) +145 e) +120

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