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Math · Statistics And Probability
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Hello, I am stuck on this question. I believe the next step is to find the Z value, however it does not make sense to me. I am comparing it to help a teacher gave me before and their z value was 2.24. If the confidence interval is 97.5% shouldn't the Z value be 1.96 which is .0975? Thanks for your help!Question 2 550 55 Is there any difference between the proportion of Americans who wish they were rich and the proportion of Canadians wish they were rich? A 500 random sample of 1,ooo Americans showed that 550 wish they were rich, while a random sample of 50o Canadians showed that 225 wished they were rich. zlo.es -0.45) 6 marks a. Find a 97.5% confidence interval for the difference between the 550 2 225 O. IO population proportions who wish they were rich. 50 Note: Express your answer to 4 decimal places of accuracy. I- O.55. 0.45 C. 45 0,55 Clooo)(o 55) 550 Ecoamee both voleues are 5 botn som sizev are lar We will use normal distribution to make idence interlae standard dev 500 Introduction to Statistics

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