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In matlab, for spectral radius how is there two values calculated on for Jacobi method and one for gauss Seidel for the same matrix?

ueI Surver function on the same linear syst Exercise 2b, specifying 1000 iterations and a tolerance of 10 , = (-0.833374653393011, 0.847258031615837, 1.246901029716106, 1.8202102328799 A2 be the following two matrices in R3X3 -6 23 2 3
mester I Lab Sheet 5 (a) Build the corresponding iteration/ matrices for the Jacobi and Gauss-Seidel methods, compute their spectral radii, and determine in each case what is the more convenient method to apply for solving the linear systems that feature these matrices. Ans: For the matrix A1, we have that the spectral radius of the iteration matrix for the Jacobi method is PJ = 0.9352, while for the Gauss-Seidel method is Pos = 0.3333, thus in this case is more convenient to use the Gauss-Seidel method. For the matrix A2, we have that the spectral radius of the iteration matrix for the Jacobi method is PJ-0.8985, while for the Gauss-Seidel method is pGs = 0.9666, thus in this case is more convenient to use the Jacobi method denondinr on the most
function x jacobi-solver(A,b,x0 ,num-iter , tol) P diag(diag(A)); IP inv(P); B IP (P-A); g = IP*b; x=x0; re1.res = norm (b-A*x) /norm(b); iter = 0; while relres > tol && iter <num.iter iter iter+1; rel-res = norm (b-A*x) /norm (b); end return Table 5.1: A possible implementation of the Jacobi method. function x gauss.seidel.solver (A,b, x0,num iter,tol) P tril(A) IP -inv (P); B = IP* (P-A) ; g = IP*b; rel-res-norm(b-A*x)/norm(b); iter = 0; while relres > tol &&iter <num.iter iter iter+1 ; rel.res norm (b-A*x)/norm(b); end return ble 5.2: A possible implementation of the Gauss-Seidel method Tabie 2 osation of the Gauss- Seidel
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