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Engineering · Electrical Engineering
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Part (a)

Unit Data for problems (1 and 2) Min Max Fuel (MW) (MW) Cost 150 250 1.40 300 1.37 H3 187+6.72(P3)-0.00043(P3)2+0.000023(P3) 3 200 4001.25 HI60+ 5.53(P1) - 0.00043(P1) 2+0.000043 (P1)A3; H2 93 + 6.63(P2) 0.0034(P2)*2 +0.000030(P2) 3; 180 (1) Lambda method: Determine the economic dispatch for a demand of 675 MW (a) Write individual unit values for lambda minimum & lambda maximum. Determine the individual units loading: P 1, P2, P3.

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