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Science · Chemistry
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please answer and explainA 0.0962 g sample of an acid of molar mass- 150.0 glmol was dissolved in 30.0 mL of water and then titrated with 0.0610 M NaoH solution. The pH of the mixture was monitored during the titration resulting in the curve shown below. Use this information to answer questions 18-21. 25.00 24.00 23.00 22.00 21.00 20.00 19.00 18.00 17.00 16.00 15.00 14.00 13.00 12.00 11.00 10.00 9.00 8.00 7.00 6.00 5.00 4.00 3.00 2.00 1.00 0.00 N N N N N N N N N N O O O O O O O O O O O O O O O O OO Volume NaOH (mL 18. The acid being titrated could be: A monoprotic or diprotic B. diprotic or triprotic C. monoprotic or triprotic D, diprotic 19. What are the approximate values of the 1st and 2nd equivalence points? C. 11.5 mL and 21.5 mL D. 9.0 mL and 19.0 mL A. 10.0 mL and 20.5 mL B. 10.5 mL and 21.0 mL 20. What are the approximate values of pKal and pKa2 D. 3.0 and 23.0 C. 4.8 and 8.5 B. 4.8 and 13.6 A. 8.5 and 18.5 21. Calculate the pH of the solution at the first equivalence point. D. 8.00 B. 8.50 C. 8.25 A. 8.75

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