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Math ยท Calculus
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Solve the following boundary value problem:

๐‘ฅ 2๐‘ฆ โ€ฒโ€ฒ โˆ’ ๐‘ฅ๐‘ฆ โ€ฒ + ๐‘ฆ = 2๐‘ฅ

๐‘ฆ(1) = 1 ๐‘Ž๐‘›๐‘‘ ๐‘ฆ(๐‘’) = ๐‘’.

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