Use variation of parameters to find a particular solution, given
the solutions y_{1}, y_{2} of the complementary
equation:

a) y'' + 4xy' + (4x^{2} + 2)y = 4e^{-x(x + 2)};
y_{1} = e^{-x^2} , y_{2} =
xe^{-x^2}

b) xy'' - (2x + 2)y' + (x + 2)y = 6x^{3}e^{x};
y_{1} = e^{x}, y_{2} =
x^{3}e^{x}

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